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प्रश्न
Evaluate (2.3a5b2) × (1.2a2b2) when a = 1 and b = 0.5.
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उत्तर
To multiply algebraic expressions, we use commutative and associative laws along with the laws of indices, i.e., \[a^m \times a^n = a^{m + n}\]
We have:
\[\left( 2 . 3 a^5 b^2 \right) \times \left( 1 . 2 a^2 b^2 \right)\]
\[ = \left( 2 . 3 \times 1 . 2 \right) \times \left( a^5 \times a^2 \right) \times \left( b^2 \times b^2 \right)\]
\[ = \left( 2 . 3 \times 1 . 2 \right) \times \left( a^{5 + 2} \right) \times \left( b^{2 + 2} \right)\]
\[ = 2 . 76 a^7 b^4\]
\[\therefore\] \[\left( 2 . 3 a^5 b^2 \right) \times \left( 1 . 2 a^2 b^2 \right) = 2 . 76 a^7 b^4\]
Substituting a =1 and b = 0.5 in the result, we get:
\[2 . 76 a^7 b^4 \]
\[ = 2 . 76 \left( 1 \right)^7 \left( 0 . 5 \right)^4 \]
\[ = 2 . 76 \times 1 \times 0 . 0625\]
\[ = 0 . 1725\]
Thus, the answer is \[0 . 1725\].
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