Advertisements
Advertisements
प्रश्न
Evaluate :
`[0.8 xx 0.8 xx 0.8 + 0.5 xx 0.5 xx 0.5]/[0.8 xx 0.8 - 0.8 xx 0.5 + 0.5 xx .5]`
Advertisements
उत्तर
`[0.8 xx 0.8 xx 0.8 + 0.5 xx 0.5 xx 0.5]/[0.8 xx 0.8 - 0.8 xx 0.5 + 0.5 xx .5]`
Let 0.8 = a and 0.5 = b
Then, the given expression becomes
`[ a xx a xx a + b xx b xx b]/[a xx a - a xx b + b xx b]`
= `[ a^3 + b^3 ]/[a^2 - ab + b^2 ]`
= `[( a + b )( a^2 - ab + b^2 )]/[a^2 - ab + b^2]`
= a + b
= 0.8 + 0.5
= 1.3
APPEARS IN
संबंधित प्रश्न
Simplify : ( x + 6 )( x + 4 )( x - 2 )
Simplify : ( x - 6 )( x - 4 )( x - 2 )
Simplify using following identity : `( a +- b )(a^2 +- ab + b^2) = a^3 +- b^3`
`( 3x - 5/x )( 9x^2 + 15 + 25/x^2)`
Simplify using following identity : `( a +- b )(a^2 +- ab + b^2) = a^3 +- b^3`
`(a/3 - 3b)(a^2/9 + ab + 9b^2)`
Find : (a + b)(a + b)
Find : (a - b)(a - b)(a - b)
Prove that : x2+ y2 + z2 - xy - yz - zx is always positive.
If a + b = 11 and a2 + b2 = 65; find a3 + b3.
Using suitable identity, evaluate (97)3
Simplify :
`[(x^2 - y^2)^3 + (y^2 - z^2)^3 + (z^2 - x^2)^3]/[(x - y)^3 + (y - z)^3 + (z - x)^3]`
