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प्रश्न
Equation of a line passing through the intersection of the lines x − y = 3 and x + y = 0 with inclination 45° is ______.
पर्याय
x + y = 3
x − y = 3
y − x = 3
y = 3x + 1
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उत्तर
Equation of a line passing through the intersection of the lines x − y = 3 and x + y = 0 with inclination 45° is x − y = 3.
Explantion:
Given,
Equations:
⇒ x − y = 3 ........(1)
⇒ x + y = 0 ........(2)
Adding equation (1) and (2), we get:
⇒ (x − y) + (x + y) = 3 + 0
⇒ x + x − y + y = 3
⇒ 2x = 3
⇒ x = `3/2`
Substituting value of x in equation (2), we get:
⇒ `3/2` + y = 0
⇒ y = `−3/2`
∴ Point of intersection of lines x − y = 3 and x + y = 0 is `(3/2,−3/2)`
Given,
Inclination (θ) = 45°
Slope = tan 45° = 1.
By point-slope form,
Equation of line: y − y1 = m(x − x1)
Equation of line passing through `(3/2,−3/2)` and slope = 1 is:
⇒ `y−(−3/2)=1(x−3/2)`
⇒ `y + 3/2 = x − 3/2`
⇒ `x − y = 3/2 + 3/2`
⇒ `x − y = 6/2`
⇒ x − y = 3
