Question

Electrolysis of dilute aqueous solution of NaCl was carried out by passing 0.01 A current. What is the time required to liberate 0.01 moles of H_2(g) at the cathode?

पर्याय

• 38.6 × 10⁴ sec

• 28.95 × 10⁴ sec

• 19.3 × 10⁴ sec

• 9.65 × 10⁴ sec

Answer 1

19.3 × 10⁴ sec

Explanation:

0.01 moles of H₂ will requires 0.02 moles of electrons or 0.02 F.

`("I" xx "t")/96500` = 0.02

`(10/1000 xx "t")/96500` = 0.02

t = 19.3 × 10⁴ sec