Advertisements
Advertisements
प्रश्न
E is the mid-point of side AB and F is the mid-point of side DC of parallelogram ABCD. Prove that AEFD is a parallelogram.
Advertisements
उत्तर
Let us draw a parallelogram ABCD Where F is the midpoint Of side DC and E is the mid-point of side AB of a parallelogram ABCD.
To prove: AEFD is a parallelogram
Proof:
In parallelogram ABCD
AB || DC
BC || AD
AB = DC
`1 /2"AB" = 1/2`DC
AE = DF
Also AD || EF
Therefore, AEFD is a parallelogram.
APPEARS IN
संबंधित प्रश्न
The alongside figure shows a parallelogram ABCD in which AE = EF = FC.
Prove that:
- DE is parallel to FB
- DE = FB
- DEBF is a parallelogram.

In the given figure, ABCD is a parallelogram.
Prove that: AB = 2 BC.

Prove that the bisectors of opposite angles of a parallelogram are parallel.
PQRS is a parallelogram. T is the mid-point of PQ and ST bisects ∠PSR.
Prove that: QR = QT
PQRS is a parallelogram. T is the mid-point of PQ and ST bisects ∠PSR.
Prove that: RT bisects angle R
PQRS is a parallelogram. T is the mid-point of PQ and ST bisects ∠PSR.
Prove that: ∠RTS = 90°
ABCD is a parallelogram. The bisector of ∠BAD meets DC at P, and AD is half of AB.
Prove that: BP bisects ∠ABC.
In the given figure, MP is the bisector of ∠P and RN is the bisector of ∠R of parallelogram PQRS. Prove that PMRN is a parallelogram.
In the following figure, it is given that BDEF and FDCE are parallelograms. Can you say that BD = CD? Why or why not?

In the following figure, ABCD and AEFG are two parallelograms. If ∠C = 55º, determine ∠F.

