Question

During estimation of Duma's method 2.36 g of an organic compound gave 448 mL of N₂ (g) at NTP. The % of N in the compound is ______.

पर्याय

• 23.7%

• 40%

• 47.4%

• 12%

Answer 1

During estimation of Duma's method 2.36 g of an organic compound gave 448 mL of N₂ (g) at NTP. The % of N in the compound is 23.7%.

Explanation: 

Wt of organic compound = 2.36 gram volume of nitrogen = 448 mL
\[\%\mathrm{N}=\frac{28\times\mathrm{V}\times100}{22400\times w}=\frac{0.125\times V}{w}\]
\[=\frac{0.125\times448}{2.36}=23.728\%\]