मराठी

Draw the structural formula of a compound with two carbon atoms in the following case: An unsaturated hydrocarbon with carbon to carbon triple bond.

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प्रश्न

Draw the structural formula of a compound with two carbon atoms in the following case:

An unsaturated hydrocarbon with carbon to carbon triple bond.

रासायनिक समीकरणे/रचना
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उत्तर

\[\ce{\underset{Ethyne}{H - C ≡ C - H}}\]

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पाठ 17: Carboxylic Acids - Exercise 4 [पृष्ठ २९३]

APPEARS IN

फ्रँक Chemistry Part 2 [English] Class 10 ICSE
पाठ 17 Carboxylic Acids
Exercise 4 | Q 1.1 | पृष्ठ २९३
एस.पी. सिंह Concise Chemistry [English] Class 10 ICSE
पाठ 12 Organic Chemistry
EXERCISE-12A | Q 11. (c) | पृष्ठ १९७

संबंधित प्रश्‍न

Which part of an organic compound determines physical properties?


Fill in the blank:

More than 90% of the known organic compounds are. ________


What is homologous series?


Give the name and strusctural formula of:

Ansaturated hydrocarbon with a double bond.


What is the special feature of the structure of Ethyne?


Give chemical equation for:

The laboratory preparation of methane from sodium acetate.


The unsaturated hydrocarbons undergo ______.


Carbon to carbon double bond is found in ______.


Give the structural formula of the following organic compound:

But-2-yne


The structures of six organic compounds are shown:

A

\[\begin{array}{cc}
\ce{H}\phantom{...}\ce{H}\phantom{...}\ce{H}\phantom{...}\ce{H}\\
|\phantom{....}|\phantom{....}|\phantom{....}|\\
\ce{H - C - C = C - C - H}\\
|\phantom{.............}|\\
\ce{H}\phantom{............}\ce{H}
\end{array}\]

B

\[\begin{array}{cc}
\phantom{.......}\ce{H}\phantom{.....}\ce{O}\\
\phantom{.......}|\phantom{.....}//\\
\ce{H - C - C}\\
\phantom{......}|\phantom{.....}\backslash\\
\phantom{...........}\ce{H}\phantom{.....}\ce{O - H}
\end{array}\]

C

\[\begin{array}{cc}
\ce{H}\phantom{...}\ce{H}\phantom{...}\ce{H}\phantom{...}\ce{H}\\
|\phantom{....}|\phantom{....}|\phantom{....}|\\
\ce{H - C - C - C - C - H}\\
|\phantom{....}|\phantom{....}|\phantom{....}|\\
\ce{H}\phantom{...}\ce{H}\phantom{...}\ce{H}\phantom{...}\ce{H}
\end{array}\]

D

\[\begin{array}{cc}
\ce{H}\phantom{...}\ce{H}\\
|\phantom{....}|\\
\ce{H - C - C - H}\\
|\phantom{....}|\\
\ce{H}\phantom{...}\ce{O}\\
\phantom{.......}\backslash\\
\phantom{.........}\ce{H}
\end{array}\]

E

\[\begin{array}{cc}
\ce{H}\\
|\\
\ce{H - C - H}\\
\ce{H}\phantom{....}\phantom{....}\ce{H}\\
|\phantom{....}|\phantom{....}|\\
\ce{H - C - C - C - H}\\
|\phantom{....}|\phantom{....}|\\
\ce{H}\phantom{...}\ce{H}\phantom{...}\ce{H}
\end{array}\]

F

\[\begin{array}{cc}
\ce{H}\phantom{...}\ce{H}\\
|\phantom{....}|\\
\ce{C = C}\\
|\phantom{....}|\\
\ce{H}\phantom{...}\ce{H}
\end{array}\]

  1. Identify two of the compounds that are members of the same homologous series but are not isomers.
  2. Which two compounds are isomers of each other?
  3. F can be prepared from D. Give a chemical equation for the reaction.

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