Question

Draw the graph for the equation given below; hence find the co-ordinates of the points where the graph is drawn meets the co-ordinates axes:
`(2x + 15)/(3) = y - 1`

Answer 1

`(2x + 15)/(3) = y - 1`
⇒ 2x + 15 = 3(y - 1)
⇒  2x + 15 = 3y - 3
⇒  2x - 3y = -15 - 3
⇒  2x - 3y = -18
⇒  -3y = -18 - 2x
⇒  y = `(-18 - 2x)/(-3)`

When x = 0,
y = `(-18-[2 xx 0])/(-3)`
= `(-18 -0)/(-3)`
= 6

When x = -3,
y = `(-18-[2 xx (-3)])/(-3)`
= `(-18 + 6)/(-3)`
= 4

When x = -6, 
y = `(-18-[2 xx (-6)])/(-3)`
= `(-18 + 12)/(-3)`
= 2

X	0	- 3	- 6
Y	6	4	2

Plotting these points we get the required graph as shown below:

From the figure it is clear that, the graph meets the coordinate axes at (-9, 0) and (0, 6).