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प्रश्न
Draw the following lines 3x + 7y = 16, x + 4 = 0 and 7y = 3x − 2. Write the coordinates of the points of intersection of the lines. What type of triangle is formed? Find its area.
आलेख
बेरीज
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उत्तर
Given:
3x + 7y = 16
x + 4 = 0 → x = −4
7y = 3x − 2
Points of Intersection:
A (–4, 4)
B (–4, –2)
C (3, 1)
Vertices: A(–4, 4), B(–4, –2), C(3, 1)
Type of Triangle: Isosceles (2 sides are equal)
= 21 square units
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