Question

Draw the chain isomer of:

\[\begin{array}{ccccccccccc} & & \mathrm{H} & & \mathrm{H} & & \mathrm{H} & & \mathrm{H} & & \mathrm{H} \\[-2pt] & & \big| & & \big| & & \big| & & \big| & & \big| \\[-2pt] \mathrm{H} & \!-\! & \mathrm{C} & \!=\! & \mathrm{C} & \!-\! & \mathrm{C} & \!-\! & \mathrm{C} & \!-\! & \mathrm{C} &\!-\!& \mathrm{H} \\[-2pt] & & & & & & \big| & & \big| & & \big| \\[-2pt] & & & & & & \mathrm{H} & & \mathrm{H} & & \mathrm{H} \end{array}\]

Answer 1

\[\begin{array}{cc}\\
\ce{CH3\phantom{........}}\\
|\phantom{...........}\\
\ce{CH2 = C - CH2 - CH3}
\end{array}\]

2-methylbut-1-ene