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प्रश्न
Draw a circle at a radius of 4 cm. Take a point on it. Without using the centre at the circle, draw a tangent to the circle at point P.
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उत्तर
Steps of Construction:
(i) Draw a chord PQ through the given point on the circle.
(ii) Take a point R on the circle and join P and Q to a point R.
(iii) Construct ∠ QPY = ∠ PRQ on the opposite sides of the chord PQ.
(iv) Produce YP to X' to get YPX as the required tangent.
Construct a tangent to the circle from an external point:
In this section we shall study the construction at tangent to a circle from an external point when its center is; (i) Know (ii) Unknown
Type (I). Construction at tangent to a circle from an external point when its centre is known.
Steps of Construction:
(i) Join the centre O of the circle to the given external point P i.e., join OP.
(ii) Draw right bisector of OP, intersecting OP at Q.
(iii) Taking Q as centre and OQ = PQ as radius, draw a circle to intersect the given circle at T and T'.
(iv) Join PT and PT' to get the required tangents as PT and PT'.
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संबंधित प्रश्न
In the given figure, PQ is a tangent to the circle at A. AB and AD are bisectors of ∠CAQ and ∠PAC. if ∠BAQ = 30°. Prove that:
- BD is a diameter of the circle.
- ABC is an isosceles triangle.
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1) AB.
2) the length of tangent PT.
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