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प्रश्न
Divide \[y^4 - 3 y^3 + \frac{1}{2} y^2 by 3y\]
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उत्तर
\[\frac{y^4 - 3 y^3 + \frac{1}{2} y^2}{3y}\]
\[ = \frac{y^4}{3y} - \frac{3 y^3}{3y} + \frac{\frac{1}{2} y^2}{3y}\]
\[ = \frac{1}{3} y^{(4 - 1)} - y^{(3 - 1)} + \frac{1}{6} y^{(2 - 1)} \]
\[ = \frac{1}{3} y^3 - y^2 + \frac{1}{6}y\]
संबंधित प्रश्न
Write the degree of each of the following polynomials.
Divide x + 2x2 + 3x4 − x5 by 2x.
Divide 4y2 + 3y +\[\frac{1}{2}\] by 2y + 1.
Verify the division algorithm i.e. Dividend = Divisor × Quotient + Remainder, in each of the following. Also, write the quotient and remainder.
| Dividend | Divisor |
| 6y5 − 28y3 + 3y2 + 30y − 9 | 2y2 − 6 |
Divide the first polynomial by the second in each of the following. Also, write the quotient and remainder:
5y3 − 6y2 + 6y − 1, 5y − 1
Find whether the first polynomial is a factor of the second.
4y + 1, 8y2 − 2y + 1
Divide:
x4 − y4 by x2 − y2
Divide:
Divide: 8x − 10y + 6c by 2
8x3y ÷ 4x2 = 2xy
