Question

Divide the following redox reaction into oxidation and reduction half-reaction.

\[\ce{Sn^2+ + 2Hg^2+ -> Sn^4+ + Hg2^2+}\]

Answer 1

Oxidation: \[\ce{Sn^2+ -> Sn^4+ + 2e-}\]

Reduction: \[\ce{2Hg^2+ + 2e- -> Hg^2+2}\]