Advertisements
Advertisements
प्रश्न
Discuss the nature of the roots of the following equation: `5x^2 - 6sqrt(5)x + 9` = 0
Advertisements
उत्तर
`5x^2 - 6sqrt(5)x + 9` = 0
Here `a = 5, b = -6sqrt(5), c = 9`
∴ D = b2 – 4ac
= `(-6sqrt(5))^2 - 4 xx 5 xx 9`
= 180 - 180
= 0
∴ D = 0
∴ Roots are real and equal.
APPEARS IN
संबंधित प्रश्न
Form the quadratic equation if its roots are –3 and 4.
In the following determine the set of values of k for which the given quadratic equation has real roots:
2x2 + kx - 4 = 0
Find the values of k for which the given quadratic equation has real and distinct roots:
kx2 + 2x + 1 = 0
If the roots of the equation (a2 + b2)x2 − 2 (ac + bd)x + (c2 + d2) = 0 are equal, prove that `a/b=c/d`.
Determine the nature of the roots of the following quadratic equation :
2x2 + x-1=0
Determine whether the given quadratic equations have equal roots and if so, find the roots:
3x2 - 6x + 5 = 0
Find the discriminant of the following equations and hence find the nature of roots: 7x2 + 8x + 2 = 0
Find the discriminant of the following equations and hence find the nature of roots: 16x2 - 40x + 25 = 0
Compare the quadratic equation `x^2 + 9sqrt(3)x + 24 = 0` to ax2 + bx + c = 0 and find the value of discriminant and hence write the nature of the roots.
If the quadratic equation kx2 + kx + 1 = 0 has real and distinct roots, the value of k is ______.
