Advertisements
Advertisements
प्रश्न
Dimensions of a painting are 60 cm × 38 cm. Find the area of the wooden frame of width 6 cm around the painting as shown in the following figure.

Advertisements
उत्तर
We have, length and breadth of inner rectangle is 60 cm and 38 cm, respectively.
∴ Area of inner rectangle = 60 × 38 = 2280 cm2 ...[∵ Area of rectangle = Length × Breadth]
∴ Breadth of outer rectangle = 38 + 6 + 6 = 50 cm
Length of outer rectangle = 60 + 6 + 6 = 72 cm ...[∵ Width of frame = 6 cm, given]
∴ Area of outer rectangle = 50 × 72 = 3600 cm2
Now, area of wooden frame = 3600 – 2280 = 1320 cm2
APPEARS IN
संबंधित प्रश्न
If the side of a square is 12 cm, find its area.
If the side of a square is tripled, how many times will its area be as compared to the area of the original square?
A page of a calendar is 45 cm long and 26 cm wide. What is its area?
If the cost of 1 sq m of a plot of land is 900 rupees, find the total cost of a plot of land that is 25 m long and 20 m broad.
Find the area of the rectangle whose sides are:
3 cm and 4 cm
How many tiles whose length and breadth are 12 cm and 5 cm respectively will be needed to fit in a rectangular region whose length and breadth are:
70 cm and 36 cm
A rectangular piece of dimensions 3 cm × 2 cm was cut from a rectangular sheet of paper of dimensions 6 cm × 5 cm (see the figure). Area of remaining sheet of paper is ______.

The perimeter of a rectangle is 40 m. Its length is four metres less than five times its breadth. Find the area of the rectangle.
A wall of a room is of dimensions 5 m × 4 m. It has a window of dimensions 1.5 m × 1 m and a door of dimensions 2.25 m × 1 m. Find the area of the wall which is to be painted.
4 squares each of side 10 cm have been cut from each corner of a rectangular sheet of paper of size 100 cm × 80 cm. From the remaining piece of paper, an isosceles right triangle is removed whose equal sides are each of 10 cm length. Find the area of the remaining part of the paper.
