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Differentiate the following w.r.t. x : sin[2tan-1(1-x1+x)] - Mathematics and Statistics

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प्रश्न

Differentiate the following w.r.t. x : `sin[2tan^-1(sqrt((1 - x)/(1 + x)))]`

बेरीज
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उत्तर

Let y = `sin[2tan^-1(sqrt((1 - x)/(1 + x)))]`

Put x = cosθ. Thenθ = cos–1x and
`sqrt((1 - x)/(1 + x)) = sqrt((1 - cosθ)/(1 + cosθ)`

= `sqrt((2sin^2(θ/2))/(2cos^2(θ/2)`

= `sqrt(tan^2(θ/2)`

= `tan(θ/2)`

∴ `tan^-1(sqrt((1 - x)/(1 + x)))`

= `tan^-1[tan(θ/2)]`

= `θ/(2)`

= `(1)/(2)cos^-1 x`

∴ y = `sin[2 xx 1/2 cos^-1 x]`
= sin (cos–1x)
∴ `"dy"/"dx" = "d"/"dx"[sin(cos-1x)]`

= `cos(cos^-1x)."d"/"dx"(cos^-1x)`

= `x xx (-1)/sqrt(1 - x^2)`

= `(-x)/sqrt(1 - x^2)`.

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पाठ 1: Differentiation - Miscellaneous Exercise 1 (II) [पृष्ठ ६४]

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बालभारती Mathematics and Statistics 2 (Arts and Science) [English] Standard 12 Maharashtra State Board
पाठ 1 Differentiation
Miscellaneous Exercise 1 (II) | Q 4.1 | पृष्ठ ६४

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