Question

Determine the work done in bringing a charge of 5 µC from infinity to the point A. The potential at point A is 400 kV.

Answer 1

Given:

Charge, q = 5 µC = 5 × 10⁻⁶ C

Potential at point A, V = 400 kV = 400 × 10³ V

The work done,

W = q × V

W = (5 × 10⁻⁶) × (400 × 10³)

W = 2 joules