Question

Determine the nature of the roots for the following quadratic equation

`9y^2 - 6sqrt(2)y + 2` = 0

Answer 1

Here a = 9, b = `-6sqrt(2)`, c = 2

∆ = b² – 4ac

= `(-6 sqrt(2))^2 - 4(9) (2)`

= 72 – 72
= 0
So the equation will have real and equal roots.