Question

Describe the action of alcoholic potassium hydroxide (alc. KOH) on isopropyl bromide.

Answer 1

Isopropyl bromide: When isopropyl bromide (2-bromopropane) is boiled with alcoholic potassium hydroxide, propene is formed.

\[\begin{array}{cc}
\ce{CH3 - CH - CH3 + \underset{(alc.)}{KOH} ->[heat] \underset{Propene}{CH3 - CH} = CH2 + KBr + H2O}\\
|\phantom{...............................................}\\
\ce{\underset{Isopropyl bromide}{Br}}\phantom{..............................................}
\end{array}\]