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महाराष्ट्र राज्य शिक्षण मंडळएचएससी विज्ञान (सामान्य) इयत्ता १२ वी

Derive the equation pH + pOH = 14.

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प्रश्न

Derive the equation pH + pOH = 14.

संख्यात्मक
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उत्तर

The ionic product of water is given as:

Kw = [H3O+][OH–]

Now, Kw = 1 × 10–14 at 298 K

Thus, [H3O+][OH–] = 1.0 × 10–14

Taking logarithm of both the sides, we write

log10[H3O+] + log10[OH–] = –14

–log10[H3O+] + {– log10[OH–]} = 14

Now, pH = –log10[H3O+] and pOH = –log10[OH–]

∴ pH + pOH = 14

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