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प्रश्न
D and E are points on the sides AB and AC respectively of Δ ABC such that AB=5.6cm, AD= 1.4cm, AC=7 .2cm and AE = 1.5 cm, show that DE is parallel to BC
बेरीज
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उत्तर
To prove : DE || BC
Sol : AB = 5.6 cm AC = 7.2 cm
AD = 1.4 cm AE = 1.8 cm
DB = 4.2 cm EC = 5.4 cm
`"AD"/"DB" = 1.4/4.2 = 1/3` ...(1)
`"AE"/"EC" = 1.8/5.4 = 1/3` ....(2)
From (1) and (2)
`"AD"/"DB" = "AE"/"EC"`
∴ DE || BC (by concerse of BPT)
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