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प्रश्न
Construct ΔXYZ in which XY = 4.5 cm, YZ = 5 cm and ZX = 6 cm.
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उत्तर
The rough figure of this triangle is as follows.
The required triangle is constructed as follows.
1) Draw a line segment YZ of length 5 cm.
2) Point X is at a distance of 4.5 cm from point Y. Therefore, taking point Y as centre, draw an arc of 4.5 cm radius.
3) Point X is at a distance of 6 cm from point Z. Therefore, taking point Z as centre, draw an arc of 6 cm radius. Mark the point of intersection of the arcs as X. Join XY and XZ.
XYZ is the required triangle.
संबंधित प्रश्न
Construct an equilateral triangle of side 5.5 cm.
Draw ΔPQR with PQ = 4 cm, QR = 3.5 cm and PR = 4 cm. What type of triangle is this?
Construct ΔABC such that AB = 2.5 cm, BC = 6 cm and AC = 6.5 cm. Measure ∠B.
Draw a triangle whose sides are of lengths 4 cm, 5 cm and 7 cm.
Construct an obtuse angled triangle which has a base of 5.5 cm and base angles of 30° and 120°.
Construct an equilateral triangle ABC of side 6 cm.
