Question

Construct a triangle with sides 5 cm, 6 cm, and 7 cm and then another triangle whose sides are `3/5` of the corresponding sides of the first triangle.

Answer 1

1. Draw a line AB = 5 cm and draw a ray from A and taking A as centre cut an arc at C of 6 cm and taking B as centre cut an arc of 7 cm at C
2. Draw AX such that ∠BAX is an acute angle.
3. Cut 5 equal arcs AA₁, A₁A₂, A₂A₃, A₃A₄, and A₄A₅.
4. Join A₅ to B and draw a line through A₃ parallel to A₅B which meets AB at B'.
    Here,  `AB' = 3/5AB`
5. Now draw a line through B' parallel to BC which joins AC at C'.
Here, `B'C' = 3/5BC  "and"  AC' = 3/5AC`
Thus, AB'C' is the required triangle.