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प्रश्न
Construct a triangle PQR with given conditions.
∠P = 115°, ∠Q = 40° and PQ = 6 cm
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उत्तर
Construction:
Step 1: Drawn a line. Marked P and Q on the line such that PQ = 6 cm.
Step 2: At P, drawn O ray PX making an angle of 115° with PQ.
Step 3: At Q, drawn another ray QY making an angle of 40° with PQ.
Marked the point of intersection of the rays PX and Q Y as R.
PQR is the required triangle.
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संबंधित प्रश्न
Given below are measurements of some parts of two triangles. Examine whether the two triangles are congruent or not, by using the SAS congruence rule. If the triangles are congruent, write them in symbolic form.
∆ABC, AB = 7 cm, BC = 5 cm, ∠B = 50°.
∆DEF, DE = 5 cm, EF = 7 cm, ∠E = 50°.
Given below are measurements of some parts of two triangles. Examine whether the two triangles are congruent or not, by using the SAS congruence rule. If the triangles are congruent, write them in symbolic form.
∆ABC, AB = 4.5 cm, AC = 4 cm, ∠A = 60°.
∆DEF, DE = 4 cm, FD = 4.5 cm, ∠D = 55°.
In Fig,
AB = AC and AD is the bisector of ∠BAC.
(i) State three pairs of equal parts in triangles ADB and ADC.
(ii) Is ∆ADB ≅ ∆ADC? Give reasons.
(iii) Is ∠B = ∠C? Give reasons.
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∠Q = 90°, ∠R = 42° and QR = 5.5 cm
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