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प्रश्न
Construct a rhombus whose perimeter is 16cm and BD = 6.2cm.
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उत्तर
The length of all the sides of rhombus is equal.
Hence, perimeter = side x 4
⇒ Side
= `"perimeter"/(4)`
= `(16)/(4)`
= 4cm
Steps of construction:
1) Draw BD = 6.2cm.
2) With B as centre and radius 4cm, draw two arcs one above BD and the other below BD.
3) With D as centre and radius 4cm draw two arcs one above BD and the other below BD intersecting the arcs of Steps 2 in A and C respectively.
4) Join AB, BC, CD and AD.
5) ABCD is the required rhombus.
संबंधित प्रश्न
Construct a rhombus ABCD, when:
Its one side = 6 cm and ∠A = 60o.
Construct a rhombus ABCD, when:
Diagonal AC = 6.3 cm and diagonal BD = 5.8 cm.
Construct a rhombus ABCD, when:
One side = 5.0 cm and height = 2.6 cm.
Construct a rhombus ABCD, when: Diagonal AC = 6.0 cm and height = 3.5 cm.
Construct a rhombus ABCD, if ;
AB = 4 cm and ∠B = 120°.
Construct a rhombus ABCD, if ;
BC = 4.7 cm and ∠B = 75°.
Construct a rhombus ABCD, if ;
CD = 5 cm and diagonal BD = 8.5 cm.
Construct a rhombus ABCD, if ;
BC = 4.8cm, and diagonal AC = 7cm.
Construct a rhombus ABCD, if ;
diagonal AC = 6 cm and diagonal BD = 5.8 cm.
Construct a rhombus ABCD, if ;
diagonal AC = 6.6 cm and diagonal BD = 5.3 cm.
