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प्रश्न
Construct a rhombus whose diagonals AC = 7.4cm and BD = 6cm.
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उत्तर
The diagonals of a rhombus bisect each other.
Steps of Construction:
1) Draw AC = 7.4cm
2) Draw perpendicular bisector to AC which cuts AC at O.
3) From this perpendicular cut OD and OB such that
OD = `"OB" = (1)/(2)"BD" = (1)/(2) xx 6"cm"` = 3cm
4) Join AB, BC, CD and AD
5) ABCD is the required rhombus.
संबंधित प्रश्न
Construct a rhombus ABCD, when:
One side = 5.0 cm and height = 2.6 cm.
Construct a rhombus ABCD, when: Diagonal AC = 6.0 cm and height = 3.5 cm.
Construct a rhombus ABCD, if ;
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Construct a rhombus ABCD, if ;
CD = 5 cm and diagonal BD = 8.5 cm.
Construct a rhombus ABCD, if ;
diagonal AC = 6 cm and diagonal BD = 5.8 cm.
Construct a rhombus ABCD, if ;
diagonal AC = 6.6 cm and diagonal BD = 5.3 cm.
Using a ruler and compasses only, construct a rhombus whose diagonals are 8 cm and 6 cm. Measure the length of its one side.
Construct a rhombus ABCD, given AB = 3.8cm and ∠A = 60°. Measure AC.
Construct a rhombus whose perimeter is 16cm and BD = 6.2cm.
Construct a rhombus whose side AB = 5cm and diagonal AC = 6cm. MEasure DB and AD.
