Question

Construct a Δ PQR in which ∠ R = 90 ° ,  PQ = 5.2 cm and QR= 2.6 cm. Complete the figure taking PR as the line of symmetry and name the figure.

Answer 1

Steps of oonstruction: 

(i) Draw a line segment QR = 2.6 cm 

(ii) At R draw a perpendicular to QR. 

(iii) With Q as centre and radius 5.2 cm cut an arc on perpendicular to R at P. 

(iv) Join PQ . Δ PQR is the required triangle. 

(v) Produce QR to S such that RS = 2.6 cm 

(vi) With S as centre and radius 5.2 cm cut an arc on perpendicular to Rat P. 

(vii) Join PS. Δ PSR is the triangle which is the reflection of &PQR. 

Δ PQS is the required triangle and is an equilateral triangle.