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प्रश्न
Consider the given data:
| Class | 0 – 20 | 20 – 40 | 40 – 60 | 60 – 80 | 80 – 100 | 100 – 120 |
| Frequencу | 15 | 30 | 50 | 63 | 35 | 32 |
The difference of lower limit of the median class and upper limit of the modal class is:
पर्याय
0
20
40
10
MCQ
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उत्तर
20
Explanation:
Finding median class:
| Class | Frequency (f) | Cumulative Frequency (cf) |
| 0 – 20 | 15 | 15 |
| 20 – 40 | 30 | 45 |
| 40 – 60 | 50 | 95 |
| 60 – 80 | 63 | 158 |
| 80 – 100 | 35 | 193 |
| 100 – 120 | 32 | 225 |
Total frequency N = 225
`N/2 = 225/2 = 112.5`
Cumulative frequency just greater than 112.5 is 158, which corresponds to class 60 – 80.
Lower limit of median class = 60
Finding modal class:
Maximum frequency is 63, which belongs to class 60 – 80.
Upper limit of modal class = 80
Calculation:
Difference = |60 – 80| = 20
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