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प्रश्न
Consider the frequency distribution of the heights of 60 students of a class:
| Height (in cm) | No. of Students | Cumulative Frequency |
| 150 – 155 | 16 | 16 |
| 155 – 160 | 12 | 28 |
| 160 – 165 | 9 | 37 |
| 165 – 170 | 7 | 44 |
| 170 – 175 | 10 | 54 |
| 175 – 180 | 6 | 60 |
The sum of the lower limit of the modal class and the upper limit of the median class is ______.
पर्याय
310
315
320
330
MCQ
रिकाम्या जागा भरा
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उत्तर
The sum of the lower limit of the modal class and the upper limit of the median class is 315.
Explanation:
The class having maximum frequency is the modal class.
So, the modal class is 150 – 155. Its lower limit is 150.
Also, N = 60 ⇒ `N/2 = 30` and the cumulative frequency just more than 30 is 37. Its class is 160 – 165, whose upper limit is 165.
Required sum = (150 + 165) = 315.
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