Question

Consider the diameter of a spherical object being measured with the help of a Vernier callipers. Suppose its 10 Vernier Scale Divisions (V.S.D.) are equal to its 9 Main Scale Divisions (M.S.D.). The least division in the M.S. is 0.1 cm and the zero of V.S. is at x = 0.1 cm when the jaws of Vernier callipers are closed.

If the main scale reading for the diameter is M = 5 cm and the number of coinciding Vernier division is 8, the measured diameter after zero error correction is:

पर्याय

• 5.18 cm

• 5.08 cm

• 4.98 cm

• 5.00 cm

Answer 1

4.98 cm

Explanation:

Given: 10 VSD = 9 MSD

`1 VSD = 9/10 MSD`

MSD = 0.1 cm

Main scale reading = 5 cm

Vernier scale reading = 8 cm

Zero error = +0.1 cm

Formula: Least Count (LC) = 1 MSD – 1 VSD

`1 MSD - 9/10 MSD`

`1/10 MSD`

`1/10 xx 0.1`

= 0.01 cm

Reading = 5 + 8 (LC) − zero error

= 5 + 8(0.01) − 0.1

= 5 + 0.08 − 0.1

= 5.08 − 0.1

= 4.98 cm