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प्रश्न
Compound A is bubbled through bromine dissolved in carbon tetrachloride, and the product is CH2Br – CH2Br.
\[\ce{A ->[Br2/CCl4] CH2Br - CH2Br}\]
- Draw the structural formula of A.
- What type of reaction has A undergone?
- What is your observation?
- Name (not formula) the compound formed when steam reacts with A in the presence of phosphoric acid.
- What is the procedure for converting the product of (iv) back to A?
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उत्तर
- CH2 = CH2
- Addition reaction
- Reddish brown colour of bromine gets discharged.
- \[\ce{\underset{Ethene}{CH2 = CH2} + H2O ->[Phosphoric][acid] \underset{Ethanol}{CH3 - CH2 - OH}}\]
- By dehydration (with any dehydrating agent).
\[\ce{\underset{Ethanol}{C2H5OH} ->[Al2O3][300^\circ C] \underset{Ethene}{C2H4} + H2O}\]
संबंधित प्रश्न
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Compound A is bubbled through bromine dissolved in carbon tetrachloride and the product is CH2Br - CH2Br.
\[\ce{A ->[Br2/Od4] CH2Br - CH2Br}\]
What is your observation
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