Question

Complete the following reaction.

\[\ce{(CH3)2CHBr  + (alc.)KOH ->[Δ][]}\]

Answer 1

\[\ce{(CH3)2CHBr  + (alc.)KOH ->[Δ][] \mathbf{\underset{\text{Propene}}{CH_3CH = CH_2} + \underset{\text{bromide}}{\underset{\text{Potassium}}{KBr}}+ H_2O}}\]