Question

Complete the following activity to find median marks of the students.

Class (Student's marks)	No. of students fi	Cumulative frequency less than the upper limit cf
0 – 20	4	4
20 – 40	20	24
40 – 60	30	54
60 – 80	40	94
80 – 100	6	100

Here, L = `square`, N = 100, `N/2 = 50`, c.f. = `square`, f = 30, h = 20

Median = `L + (N/2 - c.f)/f xx h`   ...(Formula)

= `square`   ...(Keeping values in the formula)

= `square + square/30 xx 20`

Median marks = `square`

Answer 1

Here, L = \[\boxed{40}\], N = 100, `N/2 = 50`, c.f. = \[\boxed{24}\], f = 30, h = 20

Median = `L + (N/2 - c.f)/f xx h`   ...(Formula)

= \[\boxed{40 + \frac{50 - 24}{30} \times 20}\]   ...(Keeping values in the formula)

= \[\boxed{40} + \frac{\boxed{26}}{30} \times 20\]

= `40 + 52/3`

= 40 + 17.33

Median marks = \[\boxed{57.33}\]