Question

Class	0 – 10	10 – 20	20 – 30	30 – 40	40 – 50
Frequency	3	5	7	9	11

The upper limit of the median class of the above data is:

पर्याय

• 10

• 20

• 30

• 40

Answer 1

40

Explanation:

Total frequency N = 3 + 5 + 7 + 9 + 11 = 35, so `N/2 = 17.5`. 

Cumulative frequencies are 3, 8, 15, 24, 35 the first cumulative value exceeding 17.5 is 24, which corresponds to class 30 – 40. 

Thus, the median class is 30 – 40 and its upper limit is 40.