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Choose the correct alternative : The corner points of the feasible region are (0, 0), (2, 0), (127,37) and (0,1) then the point of maximum z = 7x + y

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प्रश्न

Choose the correct alternative :

The corner points of the feasible region are (0, 0), (2, 0), `(12/7, 3/7)` and (0,1) then the point of maximum z = 7x + y

पर्याय

  • (0, 0)

  • (2, 0)

  • `(12/7, 3/7)`

  • (0, 1)

MCQ
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उत्तर

Z = 7x + y
At (0, 0), Z = 0 + 0 = 0
At (2, 0), Z = 7 (2) + 0 = 14

At `(12/7, 3/7), "Z" = 7(12/7) + (3)/(7) = (87)/(7)` = 12.428

At (0, 1), Z = 0 + 1 = 1.
The maximum value of Z is 14 and it occurs at (2, 0).

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पाठ 6: Linear Programming - Miscellaneous Exercise 6 [पृष्ठ १०३]

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बालभारती Mathematics and Statistics 2 (Commerce) [English] Standard 12 Maharashtra State Board
पाठ 6 Linear Programming
Miscellaneous Exercise 6 | Q 1.11 | पृष्ठ १०३
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