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प्रश्न
Choose the correct alternative:
`sin^-1 (tan pi/4) - sin^-1 (sqrt(3/x)) = pi/6`. Then x is a root of the equation
पर्याय
x2 – x – 6 = 0
x2 – x – 12 = 0
x2 + x – 12 = 0
x2 + x – 6 = 0
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उत्तर
x2 – x – 12 = 0
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