Question

Calculate the volume of HCl gas formed and chlorine gas required when 40 ml of methane reacts completely with chlorine at S.T.P.

\[\ce{CH4 + 2Cl2 → CH2Cl2 + 2HCl}\]

Answer 1

\[\ce{CH4 + 2Cl2 → CH2Cl2 + 2HCl}\]
1V         2V                                2V

From equation, 1V of CH₄ gives = 2 V HCl

so, 40 ml of methane gives = 80 ml of CO₂

For 1V of methane = 2V of Cl₂ required

So, for 40ml of methane = 40 × 2 = 80 ml of Cl₂