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प्रश्न
Calculate the time period of a simple pendulum of length 1.44 m on the surface of the moon. The acceleration due to gravity on the surface of the moon is 1/6 the acceleration due to gravity on earth, [g = 9.8 ms−2]
संख्यात्मक
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उत्तर
Length of simple pendulum = l = 1.44 m
Time period (T) = ?
Acceleration due to gravity on the surface of the moon
= g′ = `1/6 xx g`
g = `9.8/6`
T = `2 pi sqrt (1/g)`
T = `2 xx 22/7 xx sqrt ((1.44 xx 6)/9.8)`
T = `44/7 xx 0.9389`
T = 5.90 s
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