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प्रश्न
Calculate the monthly bill for a heater of resistance 50 Ω, which is used on 200 V mains, such that its daily use is for 4 h. The energy cost is ₹ 2.50 per kWh.
संख्यात्मक
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उत्तर
Power of heater P = $$\frac{V^2}{R}$$
$$= \frac{(200)^2}{50}$$
= 800 W
∴ Energy consumed by the heater in a day = P × t
= 800 W × 4 h
= 3200 Wh
∴ Energy consumed by the heater in 30 days (month) = 3200 Wh × 30
= 96000 Wh
= 96 kWh
∴ Monthly bill \[=96 \mathrm{kWh} \times \frac{₹ 2.5}{\mathrm{kWh}}\] = ₹ 240
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