Question

Calculate the mass of the solute in the following solution:

250 cm³ of N H₂SO₄

Answer 1

Given: Volume of solution = 250 cm³ = 0.250 L

Normality (N) = 1 N

Acid = H₂SO₄ (diprotic acid, basicity = 2)

Molar mass of H₂SO₄ = 98 g/mol

Equivalent weight of H₂SO₄ = `"Molar mass"/"Basicity"`

= `98/2`

= 49 g/eq

Mass of solute = Normality × Equivalent weight × Volume (L)

Mass = 1 × 49 × 0.250

Mass = 12.25 g

12.25 g of H₂SO₄ is present in 250 cm³ of 1 N solution.