Advertisements
Advertisements
प्रश्न
Calculate the mass of sodium sulphate required to prepare its 20% (mass percent) solution in 100g of water?
Advertisements
उत्तर
Let the mass of sodium Sulphate required to be = x g
The mass of solution would be = (x + 100) g x g of solute in (x + 100) g of solution
20% = `"x"/("x" + 100) xx 100`
20x + 2000 = 100x
80x = 2000
x = `200/80`
= 25g
APPEARS IN
संबंधित प्रश्न
Explain the term molality
Why does the molarity of a solution depend upon temperature?
Solve the following problem:
Find out the molar mass of the following compounds:
Copper sulphate crystal (CuSO4.5H2O)
(At. mass: Cu = 63.5; S = 32; O = 16; H = 1; Na = 23; C = 12; Fe = 56; N = 14)
Solve the following problem:
Perform the following calculation. Round off your answer to two digits.
`(1.4xx10^9)/((2.77xx10^3)(3.76xx10^5))`
Perform the following calculation. Round off your answer to three digits.
(8.39 107) (4.53 109)
Solve the following problem:
Perform the following calculation. Round off your answer to three digits.
`((9.28xx10^9)(9.9xx10^-7))/((511)(2.98xx10^-6))`
Solve the following problem:
The hourly energy requirements of an astronaut can be satisfied by the energy released when 34 grams of sucrose are “burnt” in his body. How many grams of oxygen would be needed to be carried in space capsule to meet his requirement for one day?
What quantity (in mL) of a 45% acid solution of a monoprotic strong acid must be mixed with a 20% solution of the same acid to produce 800 mL of a 29.875% acid solution?
250 g solution of D-glucose in water contains 10.8% of carbon by weight. The molality of the solution is nearest to ______.
(Given: Atomic weights are H, 1u; C, 12u; O, 16u)
The molarity of urea (molar mass 60 g mol−1) solution by dissolving 15 g of urea in 500 cm3 of water is ______.
