Question

Calculate the length of the second’s pendulum on the surface of the moon when acceleration due to gravity on the moon is 1.63 ms⁻².

Answer 1

Length of second’s pendulum = l =?

Acceleration due to gravity on the surface of the moon
= g_m = 1.63 ms⁻²

Time period = T = 2 s

T = `2πsqrt("l"/"g")`

2 = `2xx22/7xxsqrt("l"/1.63)`

`sqrt("l"/1.63)=7/22`

Squaring both sides

`"l"/1.63=49/484`

l = `49/484xx1.63`

l = 0.165 m