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प्रश्न
Calculate the heat energy given out by the filament of an electric bulb in 20 s, when its resistance is 4 Ω and the p.d. across its ends is 12 V.
संख्यात्मक
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उत्तर
R = 4 Ω; V = 12 V; t = 20 s
\[\text{Heat energy} = \frac{\mathrm{V}^{2} \times t}{\mathrm{R}}\]
\[= \frac{12 \times 12 \times 20}{4}\]
\[= \frac{2880}{4}\]
= 720 J
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