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महाराष्ट्र राज्य शिक्षण मंडळएचएससी विज्ञान (सामान्य) इयत्ता १२ वी

Calculate the change in angular momentum of the electron when it jumps from third orbit to first orbit in hydrogen atom.(Take h = 6.33 × 10−34 Js)

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प्रश्न

Calculate the change in angular momentum of the electron when it jumps from third orbit to first orbit in hydrogen atom.
(Take h = 6.33 × 10−34 Js)

संख्यात्मक
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उत्तर

According to Bohr's second postulate,

Angular momentum = `(nh)/(2 pi)`

For the first orbit, n1 = 1

∴ `L_1 = ((1)h)/(2 pi) = h/(2 pi)`    ...(i)

For the third orbit, n3 = 3

∴ `L_3 = ((3)h)/(2 pi) = (3h)/(2 pi)`    ...(ii)

When an electron jumps from 3rd orbit to 1st orbit, the change in angular momentum is

`L_3 - L_1 = (3 h)/(2 pi) - h/(2 pi)`

= `(2 h)/(2 pi)`

= `h / pi`

Putting h and π values, we get

Change in angular momentum = `(6.33 xx 10^-34)/3.142`

= 2.11 × 10−34 kg m2/s

The change in angular momentum of an electron when it jumps from the 3rd orbit to the 1st orbit in a hydrogen atom is 2.11 × 10−34 kg m2/s.

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