Question

Calculate pH of mixture of 400 ml of `1/200` M Ba(OH)₂ 400 ml of `1/50` M HCl and 200 ml of 50 water.

पर्याय

• 8.4

• 2.4

• 2.8

• None of these

Answer 1

2.4

Explanation:

[H⁺] = `(400 xx 1/50 - 400 xx 1/200 xx 2)/1000`

= 4 × 10^–3

pH = 3 – 2 log2 = 2.4