Question

Calculate the mass of Calcium that will contain the same number of the atom as are present in 3.2 gm of Sulphur.

[Atomic masses: S=32, Ca=40]

 

Answer 1

Given:

Mass of Sulphur = 3.2 gm

Solution:

32 g of S ≡ 6.022 × 10²³ atoms

3.2 g of S ≡?

3.2 g of S will contain =` (6.022 xx 10^23 xx 3.2)/32` = 6.022 x 10²² atoms

40 g of Ca ≡ 6.022 × 10²³ atoms

`?≡6.022 xx 10^22` atoms

Mass of Ca ≡ `(6.022 xx 10^22 xx 40)/(6.022 xx 10^(23))` = 4g

Mass of calcium = 4g