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प्रश्न
Calculate how long it will take to deposit 1.0 g of chromium when a current of 1.25 ampere flows through a solution of chromium (III) sulphate. (Atomic weight of Cr = 52, 1 Faraday = 96,500 coulombs)
संख्यात्मक
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उत्तर
Given: Atomic weight of Cr = 52
1 Faraday = 96,500 coulombs
I = 1.25 ampere
m = 1.0 g
\[\ce{Cr^{3+} + 3e^- → Cr}\]
52 g of chromium requires current = 3 × 96,500 coulombs
1 g of chromium requires current = `(3 xx 96500 xx 1)/52`
= `289500/52`
= 5567.3
Q = I × t
t = `Q/I`
= `5567.3/1.25`
= 4453.8 seconds
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