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प्रश्न
Calculate:
`(49^((-3)/2)xx7^-2)/(343^((-4)/3))`
बेरीज
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उत्तर
Given,
`(49^((-3)/2)xx7^-2)/(343^((-4)/3))`
We need to simplify the given terms.
Thus, `(49^((-3)/2)xx7^-2)/(343^((-4)/3)) = ((7^2)^((-3)/2) xx 7^-2)/((7^3)^((-4)/3)`
= `(7^(2 xx (-3)/2) xx 7^-2)/(7^(3 xx (-4)/3)` ...[∴ (am)n = amn]
= `(7^-3 xx 7^-2)/7^-4`
= `(7)^(-3 - 2)/(7)^-4` ...[∴ an × am = an + m]
= `(7)^-5/(7)^-4`
= `(7)^(-5 - (-4))` ...`[∴ a^n/a^m = a^(n - m)]`
= `(7)^(-5 + 4)` ...`[∴ a^-n = 1/a^n]`
= `7^-1`
= `1/7`
Hence, the required is `1/7`.
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पाठ 6: Indices - EXERCISE 6 [पृष्ठ ६७]
