मराठी

Calculate: 49^−3/2 × 7^−2/343^−4/3 - Mathematics

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प्रश्न

Calculate:

`(49^((-3)/2)xx7^-2)/(343^((-4)/3))`

बेरीज
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उत्तर

Given,

`(49^((-3)/2)xx7^-2)/(343^((-4)/3))`

We need to simplify the given terms.

Thus, `(49^((-3)/2)xx7^-2)/(343^((-4)/3)) = ((7^2)^((-3)/2) xx 7^-2)/((7^3)^((-4)/3)`

= `(7^(2 xx (-3)/2) xx 7^-2)/(7^(3 xx (-4)/3)`   ...[∴ (am)n = amn]

= `(7^-3 xx 7^-2)/7^-4`

= `(7)^(-3 - 2)/(7)^-4`  ...[∴ an × am = an + m]

= `(7)^-5/(7)^-4`

= `(7)^(-5 - (-4))`  ...`[∴ a^n/a^m = a^(n - m)]`

= `(7)^(-5 + 4)`  ...`[∴ a^-n = 1/a^n]`

= `7^-1`

= `1/7`

Hence, the required is `1/7`.

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पाठ 6: Indices - EXERCISE 6 [पृष्ठ ६७]

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बी निर्मला शास्त्री Mathematics [English] Class 9 ICSE
पाठ 6 Indices
EXERCISE 6 | Q 8. (i) | पृष्ठ ६७
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