Question

By taking three different values of n verify the truth of the following statement:

If n is odd, then n³ is also odd.

Answer 1

Let the three odd natural numbers be 3, 9 and 27.
Cubes of these numbers are: 

\[3^3 = 27, 9^3 = 729, {27}^3 = 19683\]

By divisibility test, it is evident that

\[27, 729 \text{ and } 19683\] are divisible by 3.

Thus, they are odd.
This verifies the statement.