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प्रश्न
|bxy + byx | ≥ ______.
पर्याय
|r|
2 |r|
r
2r
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उत्तर
|bxy + byx | ≥ 2 |r|.
Explanation:
`(bxy+b/(xy))/2≥sqrt(bxy*b/(xy))`
`(bxy+b/(xy))/2≥sqrt(b^2)`
bxy + `b/(xy)≥2b`
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